Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6, the probability of getting a sum 3, is

Let A be the event that the sum of numbers on the dice was less than 6

And, B be the event that the sum of numbers on the dice is 3


A={(1,4)(4,1)(2,3)(3,2)(2,2)(1,3)(3,1)(1,2)(2,1)(1,1)


N(A)=10


B={(1,2)(2,1)


n(B)=2


Required probability =


Required probability =


Hence, The probability is

82