State True or False for the statements in the Exercise.
If A and B are independent events, then A′ and B′ are also independent.
TRUE
As A and B are independent
⇒ P(A ∩ B) = P(A)P(B)
As, P(A’ ∩ B’) = P(A ∪ B)’ {using De morgan’s law}
As, P(A ∪ B)’ = 1 – P(A ∪ B)
As we know P(A ∪ B) = P(A) + P(B) – P(A ∩ B)
⇒ P(A ∪ B)’ = 1 –[ P(A) + P(B) – P(A ∩ B)]
⇒ P(A’ ∩ B’) = 1 - P(A) - P(B) + P(A)P(B) {as A & B are independent}
= [1 – P(A) ]– P(B) (1-P(A)]
⇒ P(A’ ∩ B’) = (1 – P(A))(1 – P(B))
= P(A’)P(B’)
hence proved