Determine the area under the curve
included between the lines x = 0 and x = a
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Squaring both sides
⇒ y2 = a2 - x2
⇒ x2 + y2 = a2
This is equation of circle having center as (0, 0) and radius a
Now in
-a ≤ x ≤ a and y ≥ 0 which means x and y both positive or x negative and y positive hence the curve
has to be above X-axis in 1st and 2nd quadrant
x = 0 is equation of Y-axis and x = a is a line parallel to Y-axis passing through (a, 0)

So we have to integrate
from 0 to a
let us find area under curve
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Integrate from 0 to a
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Using uv rule of integration where u and v are functions of x

Here
and v = 1
Hence ![]()
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But ![]()


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We know that ![]()




Hence area bounded =
unit2