The area of the region bounded by the curve x 2 = 4y and the straight line x = 4y – 2 is.

Question

Philoid · Accepted Answer

Given;

The curve x² = 4y and the straight line x = 4y – 2

By substituting for 4y;

⇒ x = x² − 2

⇒ x² − x − 2 = 0

⇒ (x + 1) (x − 2) = 0

∴ x = −1, 2.

Required area