Solve the differential equation (1+ y2) tan-1x dx + 2y (1 + x2) dy = 0

given: (1+y2) tan-1x dx + 2y(1+x2) dy=0

To find: solution of given differential equation


Re-writing the equation as




Integrating both sides



For LHS


Assume tan-1 = t



Formula:



For RHS


Assume 1+y2=z


2y dy=dz


Now substituting and integrating both sides




Formula:


Substituting for t and z




Is the solution for the given differential equation


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