The general solution of ex cosy dx – ex siny dy = 0 is:

excos y dx – exsin y dy = 0


excos y dx = exsin y dy



Integrate



Substitute cosy = t hence which means siny dy = -dt



x = -log t + c


Resubstitute t


x = -log(cosy) + c


x + c = log(cosy)-1



x + c = log(secy)


ex+c = sec y


ex × ec = sec y



excos y = e-c


As e is a constant c is the integration constant hence e-c is a constant and hence let it be denoted by k such that k = e-c


excos y = k

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