The area of the quadrilateral ABCD, where A(0,4,1), B (2, 3, –1), C(4, 5, 0)and D (2, 6, 2), is equal to

Given,


A(0,4,1), B (2, 3, –1), C(4, 5, 0) and D (2, 6, 2), therefore






Since, opposite vectors of this parallelogram are equal and opposite, therefore ABCD is a parallelogram and we know area of a parallelogram ABCD is


|AB × CD|






= 9 sq units

35