Name the octants in which the following points lie:
(i) (5, 2, 3)
(ii) (-5, 4, 3)
(iii) (4, -3, 5)
(iv) (7, 4, -3)
(v) (-5, -4, 7)
(vi) (-5, -3, -2)
(vii) (2, -5, -7)
(viii) (-7, 2, -5)
Given: Points are given
To find: name of the octant
Formula used:
Notation of octants:
If x, y and z all three are positive, then octant will be XOYZ
If x is negative and y and z are positive, then the octant will be X’OYZ
If y is negative and x and z are positive, then the octant will be XOY’Z
If z is negative and x and y are positive, then the octant will be XOYZ’
If x and y are negative and z is positive, then the octant will be X’OY’Z
If z and y are negative and x is positive, then the octant will be XOY’Z’
If x and z are negative and x is positive, then the octant will be X’OYZ’
If x, y and z all three are negative, then octant will be X’OY’Z’
(i) (5, 2, 3)
In this case, since x, y and z all three are positive then octant will be XOYZ
(ii) (-5, 4, 3)
In this case, since x is negative and y and z are positive then the octant will be X’OYZ
(iii) (4, -3, 5)
In this case, since y is negative and x and z are positive then the octant will be XOY’Z
(iv) (7, 4, -3)
In this case, since z is negative and x and y are positive then the octant will be XOYZ’
(v) (-5, -4, 7)
In this case, since x and y are negative and z is positive then the octant will be X’OY’Z
(vi) (-5, -3, -2)
In this case, since x, y and z all three are negative then octant will be X’OY’Z’
(vii) (2, -5, -7)
In this case, since z and y are negative and x is positive then the octant will be XOY’Z’
(viii) (-7, 2, -5)
In this case, since x and z are negative and x is positive then the octant will be X’OYZ’