Show that the points A(3, 3, 3), B(0, 6, 3), C(1, 7, 7) and D(4, 4, 7) are the vertices of squares.
Given: Points are A(3, 3, 3), B(0, 6, 3), C(1, 7, 7) and D(4, 4, 7)
To prove: the quadrilateral formed by these 4 points is a square
All sides of a square are equal
Formula used:
The distance between any two points (a, b, c) and (m, n, o) is given by,
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Therefore,
The distance between A(3, 3, 3) and B(0, 6, 3) is AB,
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Distance between B(0, 6, 3) and C(1, 7, 7) is BC,
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Distance between C(1, 7, 7) and D(4, 4, 7) is CD,
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The distance between A(3, 3, 3) and D(4, 4, 7) is AD,
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Clearly,
AB = BC = CD = AD
Thus, Quadrilateral formed by ABCD is a square
Hence Proved