Show that the point A(1,2, 3), B(-1, -2, -1), C(2, 3, 2) and D(4, 7, 6) are the vertices of a parallelogram ABCD, but not a rectangle.
Given: Points are A(1,2, 3), B(-1, -2, -1), C(2, 3, 2) and D(4, 7, 6)
To prove: the quadrilateral formed by these 4 points is a parallelogram but not a rectangle
Opposite sides of both parallelogram and rectangle are equal
But diagonals of a parallelogram are not equal whereas they are equal for rectangle
Formula used:
The distance between any two points (a, b, c) and (m, n, o) is given by,
Therefore,
Distance between A(1, 2, 3) and B(-1, -2, -1) is AB,
= 6
Distance between B(-1, -2, -1) and C(2, 3, 2) is BC,
Distance between C(2, 3, 2) and D(4, 7, 6) is CD,
= 6
The distance between A(1, 2, 3) and D(4, 7, 6) is AD,
Clearly,
AB = CD
BC = AD
Opposite sides are equal
Now, we will find the length of diagonals
The distance between A(1, 2, 3) and C(2, 3, 2) is AC,
Distance between B(-1, -2, -1) and D(4, 7, 6) is BD,
Clearly,
AC BD
The diagonals are not equal, but opposite sides are equal
Thus, Quadrilateral formed by ABCD is a parallelogram but not a rectangle
Hence Proved