Show that the point A(1,2, 3), B(-1, -2, -1), C(2, 3, 2) and D(4, 7, 6) are the vertices of a parallelogram ABCD, but not a rectangle.

Given: Points are A(1,2, 3), B(-1, -2, -1), C(2, 3, 2) and D(4, 7, 6)


To prove: the quadrilateral formed by these 4 points is a parallelogram but not a rectangle


Opposite sides of both parallelogram and rectangle are equal


But diagonals of a parallelogram are not equal whereas they are equal for rectangle


Formula used:


The distance between any two points (a, b, c) and (m, n, o) is given by,



Therefore,


Distance between A(1, 2, 3) and B(-1, -2, -1) is AB,






= 6


Distance between B(-1, -2, -1) and C(2, 3, 2) is BC,






Distance between C(2, 3, 2) and D(4, 7, 6) is CD,






= 6


The distance between A(1, 2, 3) and D(4, 7, 6) is AD,






Clearly,


AB = CD


BC = AD


Opposite sides are equal


Now, we will find the length of diagonals


The distance between A(1, 2, 3) and C(2, 3, 2) is AC,






Distance between B(-1, -2, -1) and D(4, 7, 6) is BD,






Clearly,


AC BD


The diagonals are not equal, but opposite sides are equal


Thus, Quadrilateral formed by ABCD is a parallelogram but not a rectangle


Hence Proved


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