Given: points A(4, 8, 10) and B(6, 10, -8)

To find: the ratio in which the line joining given points is divided by the yz-plane

Formula used:

Section Formula:

A line AB is divided by C in m:n where A(x, y, z) and B(a, b, c).

The coordinates of C is given by,

the x coordinate is always 0 on yz-plane

Let Point C(0, y, z), and C divides AB in ratio k: 1

Therefore, m = k and n = 1

A(4, 8, 10) and B(6, 10, -8)

Coordinates of C using section formula:

On comparing:

⇒ 6k + 4 = 0(k + 1)

⇒ 6k + 4 = 0

⇒ 6k = – 4

Hence, C divides AB externally in ratio 2 : 3