Given: Points A(-2, 0, 6) and B(10, -6, -12)

To find: the coordinates of points P which is five-sixth of AB

Formula used:

Section Formula:

A line AB is divided by C in m:n where A(x, y, z) and B(a, b, c).

The coordinates of C is given by,

Let AB = 6 units and Point C(x, y, z) is fifth-sixth of AB

⇒ CB = 6 – 5 = 1

Hence, AC : CB = 5 : 1

Now, we will firstly apply section formula on AB and find coordinates of C

Therefore, m = 5 and n = 1

A(-2, 0, 6) and B(10, -6, -12)

Coordinates of R using section formula:

Hence, Coordinates of C are (8, -5, -9)