The ratio in which the line joining (2, 4, 5) and (3, 5, -9) is divided by the yz-plane is

Given: points A(2, 4, 5) and B(3, 5, -9)


To find: the ratio in which the line joining given points is divided by the yz-plane


Formula used:


Section Formula:


A line AB is divided by C in m:n where A(x, y, z) and B(a, b, c).



The coordinates of C is given by,



x coordinate is always 0 on yz-plane


Let Point C(0, y, z) and C divides AB in ratio k : 1


Therefore, m = k and n = 1


A(2, 4, 5) and B(3, 5, -9)



Coordinates of C using section formula:




On comparing:



3k + 2 = 0(k + 1)


3k + 2 = 0


3k = –2



Hence, C divides AB externally in ratio 2 : 3

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