The perpendicular distance of the point P(6, 7, 8) from xy-plane is
Given: Points P(6, 7, 8)
To find: the perpendicular distance of the point P from xy-plane
As we know z = 0 in xy-plane.
The shortest distance of the plane will be the z-coordinate of the point
Hence, the distance of point P from xy-plane is 8 units