The perpendicular distance of the point P(6, 7, 8) from xy-plane is

Given: Points P(6, 7, 8)


To find: the perpendicular distance of the point P from xy-plane


As we know z = 0 in xy-plane.


The shortest distance of the plane will be the z-coordinate of the point


Hence, the distance of point P from xy-plane is 8 units

12