Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the following cases:
conjugate axis is 7 and passes through the point (3, -2).
Given: conjugate axis is 5 and passes through the point (3, -2)
To find: the equation of the hyperbola
Formula used:
For hyperbola:
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Conjugate axis is 2b
Therefore
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The equation of hyperbola is:
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Since it passes through (3, -2)

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The equation of hyperbola:
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Hence, required equation of hyperbola is 65x2 – 36y2 = 441