Find the equation of the hyperbola, referred to its principal axes as axes of coordinates, in the following cases:
conjugate axis is 7 and passes through the point (3, -2).
Given: conjugate axis is 5 and passes through the point (3, -2)
To find: the equation of the hyperbola
Formula used:
For hyperbola:
Conjugate axis is 2b
Therefore
The equation of hyperbola is:
Since it passes through (3, -2)
The equation of hyperbola:
Hence, required equation of hyperbola is 65x2 – 36y2 = 441