Find the equation of the hyperbola whose
foci are (4, 2) and (8, 2) and eccentricity is 2.
Given: Foci are (4, 2) and (8, 2) and eccentricity is 2
To find: equation of the hyperbola
Formula used:
The standard form of the equation of the hyperbola is,
Center is the mid-point of two foci.
Distance between the foci is 2ae and b2 = a2(e2 – 1)
The distance between two points (m, n) and (a, b) is given by
Mid-point theorem:
Mid-point of two points (m, n) and (a, b) is given by
Center of hyperbola having foci (4, 2) and (8, 2) is given by
= (6, 2)
The distance between the foci is 2ae and Foci are (4, 2) and (8, 2)
{∵ e = 2}
b2 = a2(e2 – 1)
The equation of hyperbola:
⇒ 3(x2 + 36 – 12x) – (y2 + 4 – 4y) = 3
⇒ 3x2 + 108 – 36x – y2 – 4 + 4y – 3 = 0
⇒ 3x2 – y2 – 36x + 4y + 101 = 0
Hence, required equation of hyperbola is 3x2 – y2 – 36x + 4y + 101 = 0