Find the equation of the hyperbola whose
foci at (± 2, 0) and eccentricity is 3/2.
Given: Foci are (2, 0) and (-2, 0) and eccentricity is
To find: equation of the hyperbola
Formula used:
The standard form of the equation of the hyperbola is,
Center is the mid-point of two foci.
Distance between the foci is 2ae and b2 = a2(e2 – 1)
The distance between two points (m, n) and (a, b) is given by
Mid-point theorem:
Mid-point of two points (m, n) and (a, b) is given by
Center of hyperbola having Foci (2, 0) and (-2, 0) is given by
= (0, 0)
The distance between the foci is 2ae, and Foci are (2, 0) and (-2, 0)
b2 = a2(e2 – 1)
The equation of hyperbola:
⇒ 45x2 – 36y2 – 80 = 0
Hence, required equation of hyperbola is 45x2 – 36y2 – 80 = 0