In a ∆ABC, if a = 5, b = 6 and C = 60o, show that its area is sq. units.

Note: In any ΔABC we define ‘a’ as length of side opposite to A , ‘b’ as length of side opposite to B and ‘c’ as length of side opposite to C .


Key point to solve the problem:



Area of ΔABC = ,where θ is the angle between sides BC and AC , a is the length of BC and b is length of AC


We have,


a = 5 , b = 6 and C = 60°


Area of ΔABC =


=


1