In a ∆ABC, if a = 5, b = 6 and C = 60o, show that its area is sq. units.
Note: In any ΔABC we define ‘a’ as length of side opposite to ∠A , ‘b’ as length of side opposite to ∠B and ‘c’ as length of side opposite to ∠C .
Key point to solve the problem:
Area of ΔABC = ,where θ is the angle between sides BC and AC , a is the length of BC and b is length of AC
We have,
a = 5 , b = 6 and ∠C = 60°
∴ Area of ΔABC =
=