For any Δ ABC show that-
Note: In any ΔABC we define ‘a’ as the length of the side opposite to ∠A, ‘b’ as the length of the side opposite to ∠B and ‘c’ as the length of the side opposite to ∠C.
Key point to solve the problem:
Idea of projection Formula:
• c = a cos B + b cos A
• b = c cos A + a cos C
• a = c cos B + b cos C
As we have to prove:
We can observe that we can get terms c – b cos A and b – c cos A from projection formula
∴ from projection formula we have-
c = a cos B + b cos A
⇒ c – b cos A = a cos B …..eqn 1
Also,
b = c cos A + a cos C
⇒ b – c cos A = a cos C ……eqn 2
Dividing eqn 1 by eqn 2, we have-
⇒ Hence proved.