In any Δ ABC, then prove that
Note: In any ΔABC we define ‘a’ as the length of the side opposite to ∠A, ‘b’ as the length of the side opposite to ∠B and ‘c’ as the length of the side opposite to ∠C.
The key point to solve the problem:
The idea of cosine formula in ΔABC
• Cos A =
• Cos B =
• Cos C =
As we have to prove under given conditions.
∵ Only cos terms are involved so we will apply cosine formula to find cos A , cos B, and cos C and we will take their ratio.
∵
∴ b + c = 12k ….eqn 1
c + a = 13k ….eqn 2
a + b = 15k ….eqn 3
But only above relation is not sufficient to find cosines as k is unknown, either we need to express k in terms of a , b or c or express a , b , c in terms of k. Later part is easier.
∴ we will find a,b,c in terms of k
Adding eqn 1,2 and 3 we have –
2 (a + b + c) = 40k
∴ a + b+ c = 20k
∴ a = 20k – (b + c) = 20k – 12k = 8k
Similarly, b = 20k – (c + a) = 20k – 13k = 7k
And c = 20k – (a + b) = 20k – 15k = 5k
Hence,
Cos A =
Cos B =
cos C =
∴
∴ ….Hence proved.