Ideas required to solve the problem:

The general solution of any trigonometric equation is given as –

• sin x = sin y, implies x = nπ + (– 1)ⁿy, where n ∈ Z.

• cos x = cos y, implies x = 2nπ ± y, where n ∈ Z.

• tan x = tan y, implies x = nπ + y, where n ∈ Z.

Given,

We know that tan x and cot x have negative values in the 2^nd and 4^th quadrant.

While giving solution, we always try to take the least value of y.

The fourth quadrant will give the least magnitude of y as we are taking an angle in a clockwise sense (i.e. negative angle)

If tan x = tan y then x = nπ + y, where n ∈ Z.

For above equation y =

∴ x = nπ + ,w here n ϵ Z

Or x = nπ - ,wh ere n ϵ Z

Thus, x gives the required general solution for the given trigonometric equation.