Find the general solutions of the following equations :
Ideas required to solve the problem:
The general solution of any trigonometric equation is given as –
• sin x = sin y, implies x = nπ + (– 1)ny, where n ∈ Z.
• cos x = cos y, implies x = 2nπ ± y, where n ∈ Z.
• tan x = tan y, implies x = nπ + y, where n ∈ Z.
Given,
We know that cos x and sec x have positive values in the 1st and 4th quadrant.
While giving solution, we always try to take the least value of y
both quadrant will give the least magnitude of y. We prefer the first quadrant.
∴
If cos x = cos y then x = 2nπ ± y, where n ∈ Z
Clearly on comparing we have y = π/3
⇒ ,where n ϵ Z ….ans