Find a point on the x-axis, which is equidistant from the point (7, 6) and (3, 4).
Key points to solve the problem:
• Idea of distance formula- Distance between two points A(x1,y1) and B(x2,y2) is given by- AB = 
As the point is on the x-axis so y-coordinate is 0.
Let the coordinate be (x,0)
Given distance of (x,0) from (7,6) and (3,4) is same.
∴ using distance formula we have:
(x - 7)2 + (0 - 6)2 = (x - 3)2 + (0 - 4)2
⇒x2 + 49 - 14x + 36 = x2 + 9 - 6x + 16
∴ point on x-axis is (7.5,0) …ans
8