Find the locus of a point such that the line segments having end points (2, 0) and (-2, 0) subtend a right angle at that point.

Key points to solve the problem:


Idea of distance formula- Distance between two points A(x1,y1) and B(x2,y2) is given by- AB =


Pythagoras theorem: In right triangle ΔABC : the sum of the square of two sides is equal to the square of its hypotenuse.


How to approach: To find the locus of a point we first assume the coordinate of the point to be (h, k) and write a mathematical equation as per the conditions mentioned in the question and finally replace (h, k) with (x, y) to get the locus of the point.


Let the coordinates of a point whose locus is to be determined to be (h, k) and name the moving point to be C.



According to a question on drawing the figure, we get a right triangle Δ ABC.


From Pythagoras theorem we have:


BC2 + AC2 = AB2


From distance formula:


BC =


AC =


And AB = 4





2h2 + 2k2 – 8 = 0


h2 + k2 = 4


Replace (h,k) with (x,y)


Thus, the locus of a point is x2 + y2 = 4 ….ans


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