To find: Transformed equation of given equation when the origin (0, 0) is shifted at point (ab/(a – b), 0).

We know that, when we transform origin from (0, 0) to an arbitrary point (p, q), the new coordinates for the point (x, y) becomes (x + p, y + q), and hence an equation with two variables x and y must be transformed accordingly replacing x with x + p, and y with y + q in original equation.

Since, origin has been shifted from (0, 0) to (1, 1); therefore any arbitrary point (x, y) will also be converted as (x + 1, y + 1) or (x + 1, y + 1).

(i) x² + xy – 3x – y + 2 = 0

Substituting the value of x by x + 1 and y by y + 1, we have

= (x + 1)² + (x + 1)(y + 1) – 3(x + 1) – (y + 1) + 2 = 0

= x² + 1 + 2x + xy + x + y + 1 – 3x – 3 - y - 1 + 2 = 0

= x² + xy = 0

Hence, the transformed equation is x² + xy = 0.

(ii) x² – y² – 2x + 2y = 0

Substituting the value of x and y by x + 1 and y + 1 respectively, we have

= (x + 1)² – (y + 1)² – 2(x + 1) + 2(y + 1) = 0

= x² + 1 + 2x - y² – 1 – 2y – 2x – 2 + 2y + 2 = 0

= x² - y² = 0

Hence, the transformed equation is x² - y² = 0.

(iii) xy – x – y + 1 = 0

Substituting the value of x and y by x + 1 and y + 1 respectively, we have

= (x + 1)(y + 1) – (x + 1) - (y + 1) + 1 = 0

= xy + x + y + 1 – x – 1 – y – 1 + 1 = 0

= xy = 0

Hence, the transformed equation is xy = 0.

(iv) xy – y² – x + y = 0

Substituting the value of x and y by x + 1 and y + 1 respectively, we have

= (x + 1)(y + 1) – (y + 1)² - (x + 1) + (y + 1) = 0

= xy + x + y + 1 – y² – 1 – 2y - x – 1 + y + 1 = 0

= xy - y² = 0

Hence, the transformed equation is xy - y² = 0.