Find the real values of x and y, if (3x – 2i y) (2 + i) 2 = 10 (1 + i)

Question

Philoid · Accepted Answer

Given:

⇒ (3x-2iy)(2+i)²=10(1+i)

⇒ (3x-2yi)(2²+i²+2(2)(i))=10+10i

We know that i²=-1

⇒ (3x-2yi)(4+(-1)+4i)=10+10i

⇒ (3x-2yi)(3+4i)=10+10i

Dividing with 3+4i on both sides

⇒

Multiplying and dividing with 3-4i

⇒

Equating Real and Imaginary parts on both sides we get

⇒

∴ The values of x and y are .