Solve the equation |z| = z + 1 + 2i.
Given:
⇒ |z|=z+1+2i
Let us assume z=x+iy
⇒ |x+iy|=x+iy+1+2i
⇒
Equating Real and Imaginary parts on both sides we get
⇒ y+2=0
⇒ y=-2-----------------------(1)
⇒ x2+(-2)2=(x+1)2
⇒ x2+4=x2+2x+1
⇒ 2x=3
∴ .