Find the modulus and argument of the following complex numbers and hence express each of them in the polar form :

sin 120o – i cos 120o

Given complex number is z=sin1200-icos1200




We know that the polar form of a complex number Z=x+iy is given by Z=|Z|(cosθ+isinθ)


Where,


|Z|=modulus of complex number=


θ =arg(z)=argument of complex number=


Now for the given problem,





|z|=1



Since x>0,y>0 complex number lies in 1st quadrant and the value of θ will be as follows 00≤θ≤900.



.



The Polar form of Z=sin1200-icos1200 is .


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