Find the modulus and argument of the following complex numbers and hence express each of them in the polar form :
sin 120o – i cos 120o
Given complex number is z=sin1200-icos1200
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We know that the polar form of a complex number Z=x+iy is given by Z=|Z|(cosθ+isinθ)
Where,
|Z|=modulus of complex number=
θ =arg(z)=argument of complex number=
Now for the given problem,
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⇒ |z|=1
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Since x>0,y>0 complex number lies in 1st quadrant and the value of θ will be as follows 00≤θ≤900.
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⇒ .
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∴ The Polar form of Z=sin1200-icos1200 is .