Prove that:
Take L.H.S.
= tan x tan (60° - x) tan (60° + x)
Multiplying & Dividing by 2:
{∵ 2 sin A sin B = cos (A – B) – cos (A + B) &
2 cos A cos B = cos (A + B) + cos (A – B)}
{cos (-A) = cos A}
{cos (180° - A) = - cos A}
Multiplying & Dividing by 2:
{∵ 2 cos A sin B = sin (A + B) – sin (A – B) &
2 cos A cos B = cos (A + B) + cos (A – B)}
= tan 3x
= R.H.S.
Hence Proved