Prove that :
cos 20° + cos 100° + cos 140° = 0
Take L.H.S:
cos 20° + cos 100° + cos 140°
{cos (180° - A) = - cos A}
= 2 cos 60° cos (-40°) – cos 40°
{cos (-A) = cos A}
= cos 40° – cos 40°
= 0
= R.H.S
Hence Proved