Prove that :
cos A + cos 3A + cos 5A + cos 7A = 4 cos A cos 2A cos 4A
Take L.H.S.
cos A + cos 3A + cos 5A + cos 7A
= (cos 3A + cos A) + (cos 7A + cos 5A)
= 2 cos 2A cos A + 2 cos 6A cos A
= 2 cos A (cos 6A + cos 2A)
= 4 cos A cos 2A cos 4A
= R.H.S.
Hence Proved