If cos (A + B) sin (C – D) = cos (A – B) sin (C + D), prove that tan A tan B tan C + tan D = 0
Given,
cos (A + B) sin (C – D) = cos (A – B) sin (C + D)
Adding 1 both sides:
Now,
Subtracting 1 both sides:
Dividing equation (i) by equation (ii):
⇒ -tan D = tan A tan B tan C
⇒ tan D = -tan A tan B tan C
⇒ tan A tan B tan C + tan D = 0
Hence Proved