Two cells of 3V each are connected in parallel. An external resistance of 0.5 Ω is connected is series to the junction of two parallel resistors of 4 Ω and 2Ω and then to common terminal of battery through each resistor as shown in figure. What is the current flowing through 4Ω resistor?
The given circuit can be reduced to : -
The equivalent resistance can be calculated as: -
Req= 
+ 0.5 = 
Ω
Req = 
Ω
The net current in the circuit is given as 
= 
A, so,
Inet = 18/11 A.
The circuit can be drawn as shown aside,
The voltage drop across the parallel resistance combination is 
, so net current in the 4 Ω resistor is 
= 0.55 A .
2